SQL PIVOT a table with no column names -


i had query returning value in list. eg:

select * some_table name in ('name1', 'name2', 'name3', 'name4', 'name5', 'name6', 'name7', 'name8', 'name9', 'name10')

i want see might not in list. eg:

select * #list name not in (select name some_table)

my list has few hundred values. how can turn list table?

select 'name1', 'name2', 'name3', 'name4', 'name5', 'name6', 'name7', 'name8', 'name9', 'name10'

into #list unpivot(?????)

create table sometable (  -- reference table     name varchar(20));  insert sometable(name) values      ('name1')     ,('name2')     ,('name3')     ,('name4')     ,('name5');   select t1.name (values                 -- list compare reference table      ('name1')     ,('name2')     ,('name129')) t1(name) except select name sometable;

this return "name129" since value in list not in reference table. same effect can achieved not exists or outer join.

select t1.name (values                 -- list compare reference table      ('name1')     ,('name2')     ,('name129')) t1(name) left outer join sometable st     on st.name = t1.name st.name null;

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