java - Why int j = 012 giving output 10? -


in actual project happened accidentally here modified small program.

i can't figure out why giving output 10?

public class int {     public static void main(string args[])     {         int j=012;//accidentaly put 0          system.out.println(j);// prints 10??     } }

after put 2 zeros still giving output 10.

than change 012 0123 , giving output 83?

can explain why ?

than change 012 0123 , giving output 83?

because, it's taken octal base (8), since numeral have 0 in leading. so, it's corresponding decimal value 10

012 : 

2 * 8 ^ 0 + 1 * 8 ^ 1 = 10

0123 : 

3 * 8 ^ 0 + 2 * 8 ^ 1 + 1 * 8 ^ 3 = 83

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