c++ - Passing initializer as argument -

does initializer have type? if so, what's? in case, how make following code work?

template <typename t> int f(t a) {     return 0; }  int main() {     f({1,2}); } 

it give following error:

c.cpp:32:2: error: no matching function call 'f' f({1,2}); ^ c.cpp:18:5: note: candidate template ignored: couldn't infer template argument 't' int f(t a) ^ 1 error generated.

when writing f({1,2}) using list initialization.

if want pass initializer list {1,2} function can this:

#include <initializer_list> #include <iostream>  template <typename t> int f(std::initializer_list<t> a) {     for(const t& x : a) {         std::cout << x << ", " << std::endl; // element     }     return 0; }  int main() {     f({1,2}); }