algorithm - How to effectively match on multiple values -

i trying come matching algorithm matches on 3 attributes , can't think of effective solution. here psuedocode algorithm

the algorithm following:

• check if there match on first criteria.
• if there match on first criteria try narrow match down based on other 2 criterias.
• if there no match on first criteria, try make match on second criteria.
• if there match on second criteria, try narrow match down based on last criteria.
• etc...

it seems algorithm repeats itself, , if add value match on, algorithm grows large real quickly.

//try match on criteria 1 if results exist match on criteria 1 {     //try match on criteria 1 & 2     if results exist match on criteria 1 & 2 {         //try match on criteria 3         if result exist match on criteria 1,2,3 {             return results match on 1,2,3         }         else             return results match on 1,2     }     else         return results match on 1 } //try match on criteria 2 else if results exist match on criteria 2 {     //try match on criteria 2 & 3     if result exist match on criteria 2,3 {         return results match on 2,3     }     else         return results match on 2 } //try match on criteria 3 else if results exist match on criteria 3 {     return results match on 3 } else {     no match } 

is there better way this? seems

here implementation in javascript if understand correctly.

function filter(arr, condition) {   var retval = [];   (i in arr) if (condition(arr[i])) retval.push(arr[i]);   return retval; }  function first_match(arr, conditions) {   if (conditions.length == 0) return("no match");   var initial_arr = array.prototype.slice.call(arr);   var prev_arr;   var = 0;   (; < conditions.length && arr.length != 0; i++) {     prev_arr = array.prototype.slice.call(arr);     arr = filter(arr, conditions[i]);   }   if (i <= 1 && arr.length == 0) return first_match(initial_arr, array.prototype.slice.call(conditions, 1));   else if (i == conditions.length && arr.length != 0) return arr;   else return prev_arr; } 

examples

var conditions = [function(x) { return x > 3; },                   function(x) { return x % 2 == 0; },                   function(x) { return math.sqrt(x) % 1 == 0; }];  var example1 = [1,2,3,4,5,6,7,8,9,10]; console.log(first_match(example1, conditions)); // [4] - 3 hold var example2 = [1,2,3,5,6,7,8,9,10]; console.log(first_match(example2, conditions)); // [6, 8, 10] - first 2 hold var example3 = [5, 7, 9]; console.log(first_match(example3, conditions)); // [5, 7, 9] - first 1 holds var example4 = [-2, 0, 2]; console.log(first_match(example4, conditions)); // [0] - 2 & 3 hold var example5 = [-2, 2]; console.log(first_match(example5, conditions)); // [-2, 2] - 2 holds var example6 = [1]; console.log(first_match(example6, conditions)); // [1] - last 1 holds var example7 = [-1]; console.log(first_match(example7, conditions)); // "no match" - none hold