c - Save int as a char? -

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i'm trying save integer character.

char = 80; printf("0x%x", i);

the above code displays 0x50 (1 byte). if value above 128, prints 4 byte value.

char = 130; printf("0x%x", i); // prints 0xffffff82

how can store integer value 1 byte if value greater 128 (print 82 instead of ffffff82 in second example) ?

this expected behavior on systems char type signed: negative values of char sign-expanded size of int.

if print last 8 bits, mask 0xff, this:

printf("0x%x", & 0xff); // prints 80

an alternative approach use unsigned char. avoid sign extension 8-bit numbers significant bit set 1.

Brazzel