Displaying two digit numbers in assembly? -


i new assembly programming. in of examples @ classwork required add 2 numbers , display sum, find cryptic display sum when 2 digit number. here's code.

    mov al,num1     mov bl,num2      add al,bl      add ax,3030h      mov dl,ah     mov ah,02h     int 21h      mov dl,al     mov ah,02h     int 21h      mov ah,4ch     int 21h

while addition might result in packed number, how unpack , display 2 different numbers in decimal?

i'm new assembly. think you.

  .model small .stack 100h .data      msg1 db "enter number 1:$"     msg2 db "enter number 2:$"     msg3 db "sum is:$"     no1 db 0     no2 db 0     mysum db 0     rem db 0   .code      mov ax,@data      mov ds,ax  ;print msg 1     mov dx,offset msg1      mov ah,09h     int 21h  ;read input no1     mov ah,01h     int 21h     sub al,48     mov no1,al  ;print new line     mov dl,10     mov ah,02h     int 21h  ;print msg2     mov dx,offset msg2     mov ah,09h     int 21h  ;read input 2     mov ah,01h     int 21h     sub al,48     mov no2,al  ;print new line      mov dl,10     mov ah,02h     int 21h  ;print msg3     mov dx,offset msg3     mov ah,09h     int 21h  ;add 2 numbers     mov dl,no1     add dl,no2     ;moving sum mysum     mov mysum,dl      ;clear ah use reminder     mov ah,00     ;moving sum al     mov al,mysum     ;take bl=10     mov bl,10     ;al/bl --> twodigit number/10 = decemel value     div bl     ;move reminder rim     mov rem,ah     ;to print (al) move al dl     mov dl,al     add dl,48     mov ah,02h     int 21h      ;to print reminder     mov dl,rem     add dl,48     mov ah,02h     int 21h      mov ax,4c00h     int 21h end

here i've done took total , move al can keep it. divide 10 , print quotient , reminder. if feel problem. can ask. thank !


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