php - display last comment at the top of the list -


i have script add comment db ajax , print on screen, @ end of previous comments

how can change new comment (the 1 user add) appear @ top of comments?

$(function() {     $(".addcomment").click(function(){          var element = $(this);         var refid = element.attr("id");         var userid = element.attr("userid");         var main = $("#main:checked").val();         var contenttext = $("#contenttext").val();         var act = 'add';         var info = 'refid=' + refid + '&userid=' + userid + '&main=' + main + '&contenttext=' + contenttext + '&act=' + act;     //  alert(info);          $("#loading").html('<img src="loader.gif" align="absmiddle">&nbsp;loading...');           $.ajax({             type: "post",             url: "ajax/comments.php",             data: info,             success: function(response){             $("#loading").ajaxcomplete(function()             {             }).slideup();              document.getelementbyid("contenttext").value="";              $("#comments").append(response);         //  $('.formcomment'+ownerid).fadeout(200).hide();         //  $('.formcomment'+ownerid).fadein(200).show();            }          });          return false;     }); });           <ul id="comments">             <?php                 $query = mysql_query("select * `comments` (userid = '$_session[userid]') order date desc");                  while($index = mysql_fetch_array($query))                 {                   echo '<li id="comment_'.$index["id"].'">';                       echo '<a href="#" class="del_button" id="del-'.$index["id"].'">';                         echo '<img src="images/icon_del.gif" border="0" />';                       echo '</a>';                   echo $index["text"].'</li>';                 }                                ?>         </ul>

php page:

if(mysql_query("insert comments (userid, pagename, refid, text, main, date) values ('$_post[userid]', 'yard', '$_post[refid]', '$contenttosave', '$_post[main]', '$datelx') ") ) {      //record inserted, respond result index page       $commentid = mysql_insert_id(); //get id of last inserted row mysql       echo '<li id="comment_'.$commentid.'">';         echo '<a href="#" class="del_button" id="del-'.$commentid.'">';             echo '<img src="../images/deletes.png" border="0" />';         echo '</a>';       echo $contenttosave.'</li>';     //  mysql_close($connecdb); //close db connection  }

change line:

 $("#comments").append(response);

to:

 $("#comments").prepend(response);

http://jsfiddle.net/cxnf5/


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