How do I declare a base model class in Flask-SQLAlchemy? -


i declare base class other schema objects can inherit from, example: 

class base(db.model):     created_on = db.column(db.datetime, default=db.func.now())     updated_on = db.column(db.datetime, default=db.func.now(), onupdate=db.func.now())

then other schema objects can inherit , not have repeat declaration of 2 columns.

how in flask-sqlalchemy? 

from flask.ext.sqlalchemy import sqlalchemy db = sqlalchemy(app)  class user(db.model):     __tablename__ = 'users'     id = db.column(db.integer, primary_key = true)     email = db.column(db.string(255), unique = true)

sqlalchemy offers directive called __abstract__. can use tell sqlalchemy not create table particular model. model can used base class.

from flask.ext.sqlalchemy import sqlalchemy db = sqlalchemy(app)  class base(db.model):     __abstract__ = true      created_on = db.column(db.datetime, default=db.func.now())     updated_on = db.column(db.datetime, default=db.func.now(), onupdate=db.func.now())   class user(base):     __tablename__ = 'users'     id = db.column(db.integer, primary_key = true)     email = db.column(db.string(255), unique = true)

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