php - *nix: Performing nested -exec with find command -


i'm trying following thing: hunt down 777 directories, , within directories, hunt down php files contain string "mail(". goal make part of cron-job runs every night , finds of php files contain mail functions may have been inserted surreptitiously onto our server. so, i've written command:

find -type d -perm 777 -exec find {} -name "*.php" \; -exec grep "mail(" {} \;

which (is supposed to):

1: find folders 777 privileges

2: each such folder, find php files contained therein

3: each such file, perform grep find string "mail("

however, doesn't appear working. doing giving me list of php files in 777-privileged directories, it's not performing grep. i've looked @ postings this:

find -exec multiple commands

which lead me believe nesting of -exec possible. there obvious i'm missing? in advance time!

you can't nest find -exec, can nest sh in turns calls find -exec. gnu find, have rewrite {} in inner find outer find won't replace it:

find . -type d -perm 777 \   -exec sh -c 'find "$1" -name "*.php" -exec grep "mail(" {""} \;' _ {} \;

this direct answer question. there multiple ways of simplifying it:

find . -type d -perm 777 \   -exec find {} -name '*.php' -print0 \; | xargs -0 grep -h 'mail('

and simpler 90% version use grep recurse:

find . -type d -perm 777 -exec grep -hr 'mail(' \; | grep '\.php'

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