Equally distribute a list in python -


suppose have following list in python:

a = ['a','b','c','d','e','f','g','h','i','j']

how distribute list this:

['a','f'] ['b','g'] ['c','h'] ['d','i'] ['e','j']

and how achieve if have list of unequal length , putting 'superfluous' items separate list?

i want able distribute elements of original list n parts in indicated manner.

so if n=3 be:

['a','d','g'] ['b','e','h'] ['c','f','i']

and 'superfluous' element in separate list

['j']

you can use zip list comprehension:

def distribute(seq):     n = len(seq)//2  #will work in both python 2 , 3     return [list(x) x in zip(seq[:n], seq[n:])]  print distribute(['a','b','c','d','e','f','g','h','i','j']) #[['a', 'f'], ['b', 'g'], ['c', 'h'], ['d', 'i'], ['e', 'j']]

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