c - How do I skip a part of standard input with scanf? -

i'm writing c program, , standard input looks this.

2 1 3 4 6 9 1 3 6 0 3 5 1 2 6 1 

my c program stores first number in variable called rowtoconsider. read rowtoconsiderth row (0-indexed) of numbers array nums.

#include<stdio.h>  int main() {   int rowtoconsider;   int nums[3];    scanf("%d", &rowtoconsider);    (int = 0; < rowtoconsider; i++) {     // attempt read row nothing. basically, skip row.     scanf("%d %d %d");   }    scanf("%d %d %d", nums, nums + 1, nums + 2);   } 

however, scanf within loop triggering segmentation fault.

how skip rows before reading in array of 3 ints?

you getting segfault because first call scanf expects 3 more arguments.

you can specify optional argument *, e.g. scanf("%*s"); read string , discard it.

from scanf man page:

an optional '*' assignment-suppression character: scanf() reads input directed conversion specification, discards input. no corresponding pointer argument required, , specification not included in count of successful assignments returned scanf().