awk - bash script for comparing -


i trying write bash script.

i on amazon-s3. have bucket1, contains bucket2, bucket3, bucket4. bucket 2 has b1, b2, b3, b4, b5 - in each of them contain tar files being created nd file name.

when s3cmd --recursive ls s3://bucket1/bucket2/ | awk '{print$1}' print date of tar files generated.

i want date on computer compare list , print last 1 week of files have been created.

format of date on s3 : year/month/date

thank you.

you can use gnu +%s option seconds, , compare dates in whatever format, i.e.

> (( ( $(date +%s) - $(date -d "2014/03/08" +%s) ) < (7*24*60*60) )) \ && echo "less week ago" \ || echo "more week ago" more week ago  > (( ( $(date +%s) - $(date -d "2014/04/03" +%s) ) < (7*24*60*60) )) \ && echo "less week ago" \ || echo "more week ago" less week ago

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