Java OOP-Accessing the last element in an array of objects -


i practicing object orientation here entering in basketball player names , how many points scored , rebounds grabbed.

how go through each element in array of objects find last player amount of points?

this code have far enter information. need in second forloop examine each element , display last element fits criteria?

class basketballobj {     public static void main (string[]args)     {         basketball bbarray[];         string thename;         int thepoints;         int therebounds;         int index;         int noofelements = 0;          bbarray = new basketball[3];          for(index = 0; index < bbarray.length; index++)             {                 system.out.println("enter name ");                 thename = easyin.getstring();                 system.out.println("enter points scored ");                 thepoints = easyin.getint();                 system.out.println("enter rebounds grabbed ");                 therebounds = easyin.getint();                 bbarray[index] = new basketball(thename, thepoints, therebounds);                 noofelements++;              }         for(index = 0; index < bbarray.length; index++)             {                 if(bbarray[index].getpoints() % 2 == 0)                     {                      }             }     } }

well if want find last player amount of points, don't want go through each element ;-). try:

for(index = bbarray.length-1; index >= 0; index--)         {             if(bbarray[index].getpoints() % 2 == 0)                 {                    //add whatever relevant code here.                    break; //this line breaks loop (because you've found player amount of score                 }         }

we start @ bbarray.length-1 because while array contains 3 elements, arrays zero-indexed. meaning first element, have call bbarray[0]. call bbarray[2] last element.


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