bash functions arguments in single quotes -


i trying pass 2 arguments following bash function $1 , $2. if echo below statement seems output $1 , $2. need have arguments in single quotes function work correctly. doing wrong?

function mysql_diff() {     java -jar mysql-diff.jar 'jdbc:mysql://localhost:3306/$1?user=root&password=password' 'jdbc:mysql://localhost:3306/$2?user=root&password=password' }

it seems need arguments enclosed in single quotes. achieve that, enclose in double quotes:

function mysql_diff() {     java -jar mysql-diff.jar "'jdbc:mysql://localhost:3306/$1?user=root&password=password'" "'jdbc:mysql://localhost:3306/$2?user=root&password=password'" }

this not prevent variable expansion , result in arguments being enclosed in single quotes.


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