preg replace - remove   if is not in front one of this character !?:;% -


i remove   if not in front 1 of character !?:;% preg_replace ( supose ) .

<div>&nbsp;hello&nbsp;! &nbsp;&nbsp;&nbsp;&nbsp; 100&nbsp;% clear&nbsp;?&nbsp;</div>

it should give me

<div>hello&nbsp;! 100&nbsp;% clear&nbsp;?</div>

thanks in advance

use negative lookahead:

$str = preg_replace('/&nbsp;(?![!?:;%])/', '', $str);

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