php - Undefined variable, why? -

i don't understand why variables $return , $id undefined...

error:

notice: undefined index: id in c:\inetpub\wwwroot\inc\classes\users.php on line 49  notice: undefined variable: return in c:\inetpub\wwwroot\inc\classes\users.php on line 49 

code:

public static function getfollowers($id) {     $query = db::query('select id_follower '.table_followers.' id_user = "'.db::escape($id).'"');     while($array = db::fetch_assoc($query))     {         $return .= '<img style="margin-left: 2px;" id="img-round" src="'.users::useravatar($array['id']).'" width="40" height="40" />';     }             return $return; } 

line 49:

            $return .= '<img style="margin-left: 2px;" id="img-round" src="'.users::useravatar($array['id']).'" width="40" height="40" />'; 

thanks.

to address second issue, first initiate variable before concatenating onto it:

public static function getfollowers($id) {     $return = ''; /* here */     $query = db::query('select id_follower '.table_followers.' id_user = "'.db::escape($id).'"');     while($array = db::fetch_assoc($query))     {         $return .= '<img style="margin-left: 2px;" id="img-round" src="'.users::useravatar($array['id']).'" width="40" height="40" />';         /* return $return; -- move outside while() loop */     }     return $return; /* moved here */ } 

to address first, $array has no key-pair id. verify exists before trying use it:

    if ( isset( $array['id'] ) ) $return .= '<img style="margin-left: 2px;" id="img-round" src="'.users::useravatar($array['id']).'" width="40" height="40" />'; 

as mentioned in comments, you're trying access $array['id'] when mean accessing $array['id_follower']