python - Pythonic random list of booleans of length n with exactly k Trues -

say want list of n 0/1 elements k instances of 1. there 1 line comprehension or more pythonic way following?

def random_include(n, k):     ret = []     to_include = set(random.sample([i in range(n)], k))     in range(n):          if in to_include:             ret.append(1)         ret.append(0) 

here's one-line solution.

output = sorted([1] * k + [0] * (n - k), key=lambda k: random.random())