r - Replace 0 with data from another array -


i want replace 0 (missing data) data array.

both data has 2013~1995 january ice sheet data, , want analyze temperature data (in column 3), 4464 temperatures data.

partial data looks this: erinjan[,,1]

            [,1] [,2]  [,3]  [,4]  [,5] [,6]  [,7]  [,8]     [1   ,]   21   10   0.0   0.0  0.0    0  0.0    0     [2   ,]   21   11   0.0   0.0  0.0    0  0.0    0     [3   ,]   21   12 -16.3 867.4  0.0    0  0.0    0     [4   ,]   21   13 -16.4 867.5  6.9   81 63.2    0     [5   ,]   21   14 -16.5 867.2  7.6   83 63.0    0     [6   ,]   21   15 -16.5 867.1  7.9   84 63.0    0     [7   ,]   21   16   0.0 867.1  8.0   86 62.0    0     [8   ,]   21   17 -16.3 867.0  8.4   87 62.0    0     [9   ,]   21   18   0.0 866.9  8.3   85 62.0    0

and harryjan[,,1] looks like:

            [,1] [,2]  [,3]  [,4]  [,5] [,6]  [,7]  [,8]     [1   ,]   21   10 -12.4 877.6   2.5   52 444.0   9.1     [2   ,]   21   11 -12.6 877.6   3.0   55 444.0   9.1     [3   ,]   21   12 -12.9 877.5   3.8   52 444.0   9.1     [4   ,]   21   13 -13.0 877.5   3.6   53 444.0   9.1     [5   ,]   21   14 -12.9 877.3   3.3   51 444.0   9.1     [6   ,]   21   15 -13.0 877.3   4.1   53 444.0   9.1     [7   ,]   21   16 -13.2 877.1   3.6   53 444.0   9.1     [8   ,]   21   17 -13.4 877.3   3.3   45 444.0   9.1     [9   ,]   21   18 -13.4 877.3   3.6   48 444.0   9.1

both array has same format , same type of data above. goal replace erinjan[,3,1] missing data harryjan[,3,1] , on. example, erinjan[1,3,1] missing data, need replace harryjan[1,3,1]. (0 replaced -12.4.)

if can code this:

   (i in 1: 19){         if erinjan[,3,i] == 0 {             replace value using harryjan         }         else {             nothing         }      }

is possible? not sure command should use. replace?

i'd appreciate help.

if understand question, this:

erinjan[erinjan == 0] <- harryjan[erinjan == 0]

would make replacement across whole matrix. not sure how columns arranged, if pull out column 3s, should able same replacement variable.

i believe work column 3 only:

erinjan[,3,][erinjan[,3,]==0] = harryjan[,3,][erinjan[,3,]==0]

this works indexing elements of first array equal 0 , using same indices pull values second array.

if find stuff in square brackets confusing, here way break out in 2 steps:

janind = which(erinjan[,3,]==0) erinjan[,3,][janind] = harryjan[,3,][janind]

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