c - Declaring and accessing 2D array -

how can use array pointer (int *) create , print kind of 2d array:

0 1 2 3 4 5 6 7 8... 1 2 3 4 5 6 7 8 9... 2 3 4 5 6 7 8 9 10... 3 4 5 6 7 8 9 ... 4 5 6 7 8 9... 5... 

i have code:

#include <stdio.h> #include <stdlib.h>  void creatematrix(int * matrix, int row, int column) {     puts("begin creating matrix.");     int i, j;     for(i = 0; < row; i++)     {         for(j = 0; j < column; j++)         {             *(matrix) = + j;             matrix++;         }     }     puts("success!"); }  int printmatrix(int * matrix, int row, int column) {     puts("begin printing matrix!");     int i, j, valuesprinted;     for(i = 0; < row; i++)     {         for(j = 0; j < column; j++)         {             printf("%5d ", *(matrix + * j));             valuesprinted++;         }         puts("");     }     puts("printing success!");     return valuesprinted; }  int main() {     int row = 11;     int column = 13;     int * matrix = malloc(sizeof(int) * row * column);      creatematrix(matrix, row, column);     printmatrix(matrix, row, column);     return 0;    } 

what want is: use declare array , assign pointer, pass pointer function , give values above. think problem in way initialize 2d array pointer , access it.

and result is:

    0     0     0     0     0     0     0     0     0     0     0     0     0     0     1     2     3     4     5     6     7     8     9    10    11    12     0     2     4     6     8    10    12     2     4     6     8    10    12     0     3     6     9    12     3     6     9    12     3     6     9    12     0     4     8    12     4     8    12     4     8    12     4     8    12     0     5    10     3     8    13     6    11     4     9    14     7    12     0     6    12     6    12     6    12     6    12     6    12     6    12     0     7     2     9     4    11     6    13     8    15    10    17    12     0     8     4    12     8     4    12     8    16    12     8    16    12     0     9     6     3    12     9     6    15    12     9    18    15    12     0    10     8     6     4    14    12    10     8    18    16    14    12 

int *matrix = malloc(sizeof(int) * row * column); // better written int *matrix = malloc((row*column) * sizeof *matrix); 

the above statement dynamically allocates array of integers of size row * column. if want access elements of array access elements of 2d array, element @ row i , column j has index

i * column + j 

modify printmatrix function -

int printmatrix(int * matrix, int row, int column) {     puts("begin printing matrix!\n");     int i, j, valuesprinted;     for(i = 0; < row; i++)     {         for(j = 0; j < column; j++)         {              // equivalent , more readabable             // printf("%5d ", matrix[i*column + j]);             printf("%5d ", *(matrix + i*column + j));                                       //  ^ note multiplied column             valuesprinted++;         }         puts("");     }     puts("printing success!\n");     return valuesprinted; }