java method overload inheritance and polymorphism -


here's test practice question came across, appreciate in making me understand concepts

let hawk subclass of bird. suppose class has 2 overloaded methods void foo(hawk h) , void foo(bird b). version executed in call foo(x) after declaration bird x = new hawk();

here's code have far, explain me why foo(bird b) gets executed?

public class mpractice {     public static void main(string args[]) {         bird x = new hawk();         third y = new third();         y.foo(x);     }  }     public class third {     void foo(hawk h) {         system.out.println("hawk");     }     void foo(bird b) {         system.out.println("bird");     }   }

when java performs overload resolution choosing methods, uses type of variable, not runtime type of object, choose method. type of x bird, third method chosen foo(bird).

this because polymorphism isn't involved here; we're not calling potentially overridden method on bird variable x, we're calling 1 of set of overloaded methods on unrelated class, third.


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