Java Path interface and OCPJP7 Exam -


i’m preparing ocpjp7 exam on these days. got 2 questions , accepting answers. first 1 relevant java , other 1 exam achievements.

import java.nio.file.*; class test13{    public static void main(string arfd[]){         path = paths.get("d:\\ocpjp7\\programs\\..\\nio2\\src\\.\\subpath.java");        a=a.normalize();        system.out.println(a);     }  }

  1. according above code segment, expected output “d:\ocpjp7\programs\nio2\src\subpath.java” not. provides “d:\ocpjp7\nio2\src\subpath.java”

    as know normalize() removes redundant elements given path including single dot , double dot. why removes \programs\ element?

  2. in order oracle certified professional, java 7 programmer, have sit 2 exams;

    oca -jp (oracle certified associate, java 7 programmer).

    java se 7 programmer.

    as know can achieve both exams in order. i’m intended first java se 7 programmer , oca.

    my question offer oracle, after passing both exams. offering 2 certificates both exams? or 1 certificate both? , else?

as know normalize() removes redundant elements given path including single dot , double dot. why removes \programs\ element?

.. refers the parent directory. in other words, /programs brings forward , /.. brings back.

the javadoc of path#normalize() states

if ".." preceded non-".." name both names considered redundant (the process identify such names repeated until no longer applicable).

so \\programs\\.. redundant , removed.

i can't answer second question.


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