mysql - Error in PHP code accessing the SQL -


this question has answer here:

the code mean't connect database. did work stopped working, i've tried reading error code shown below can't seem fix it. here unworking code:

<?php     mysql_connect("127.0.0.1", "goaerox_lkdb1", "~censored~"); //your parameters here     mysql_select_db("goaerox_lkdb1"); //you db name here      $q = "select id, channel, email, paypal, network partners;";     $result = mysql_query($q);      echo "<table>";     echo "<tr><td>id</td><td>channel</td><td>email</td><td>paypal</td><td>network </td><td>actions</td></tr>";     while ($row = mysql_fetch_array($result, mysql_num)) {         echo "<tr>";         echo "<td>".$row[0]."</td>";         echo "<td>".$row[1]."</td>";         echo "<td>".$row[2]."</td>";         echo "<td>".$row[3]."</td>";         echo "<td>".$row[4]."</td>";         echo "</tr>";     }     echo "</table>";      mysql_free_result($result);      ?>

now have seen that, should have better understanding on meant do. current error getting: 

warning: mysql_fetch_array() expects parameter 1 resource, boolean given in public_html/test.php on line 10 id  channel email   paypal  network actions warning: mysql_free_result() expects parameter 1 resource, boolean given in public_html/test.php on line 21

if please me appreciated.

please note mysql_ functions deprecated. aside that, problem can explained via following sentence the documentation:

for select, show, describe, explain , other statements returning resultset, mysql_query() returns resource on success, or false on error.

what happening select statement not retrieving database results, getting false return value, boolean value. subsequently, mysql_fetch_array() function failing because first parameter passing not resource, expected, boolean value false.


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